A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.24 hours, with a standard deviation of 2.49 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.08 hours, with a standard deviation of 1.59 hours. Construct and interpret a 90% confidence interval for the mean difference in leisure time between adults with no children and adults with children (H1 - H2) . . . . . . Let py represent the mean leisure hours of adults with no children under the age of 18 and 2 represent the mean leisure hours of adults with children under the age of 18. The 90% confidence interval for ( H1 - H2 ) is the range from hours to hours. (Round to two decimal places as needed.) What is the interpretation of this confidence interval? O A. There is a 90% probability that the difference of the means is in the interval. Conclude that there is a significant difference in the number of leisure hours. O B. There is a 90% probability that the difference of the means is in the interval. Conclude that there is insufficient evidence of a significant difference in the number of leisure hours. O C. There is 90% confidence that the difference of the means is in the interval. Conclude that there is a significant difference in the number of leisure hours. O D. There is 90% confidence that the difference of the means is in the interval. Conclude that there is insufficient evidence of a significant difference in the number of leisure hours