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A raw wastewater has a flowrate of 1 0 , 0 0 0 m 3 d and an influent BOD concentration of 2 5 0

A raw wastewater has a flowrate of 10,000m3d and an influent BOD concentration of 250mgL. The primary clarifier removes 30% of the BOD prior to secondary treatment. The permit requires that the effluent BOD5 be 17mgL or less and the TSS concentration be less than 18mgL. Use the low-end values for the values of growth constants for domestic wastewater given in your textbook (Table 8-10). Assume the mixed liquor concentration will be 2,500mgL in the aeration basin and the VSS:TSS ratio is 0.80(VSS =80%TSS) in the effluent. Determine the following:
a. Effluent soluble BOD5 concentration in mgL
b. Mean cell residence time (d)
c. Hydraulic detention time (hr)
d. Volume of the aeration basin (gal)
e. Mass of BOD substrate consumed per day (kgd
f. Waste activated sludge produced per day (kgd)
g. Oxygen requirements ((bd) assuming that BOD5=65%(BODu)
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