A recent study claimed that 45% of the population of all college students prefer printed textbooks to electronic textbooks. You Espan want to test this claim by surveying a random sample of 45 college students. Follow the steps below to construct a 90% confidence interval for the population proportion of all college students who prefer printed textbooks to electronic textbooks. Then state whether the confidence interval you construct contradicts the study's daim. (If necessary, consult a list of formulas.) (a) Click on "Take Sample" to see the results from the random sample. Number Proportion Take Sample Prefers printed textbooks to electronic textbooks 27 0.6 Does not prefer printed textbooks to electronic 18 0.4 textbooks Enter the values of the sample size, the point estimate of the population proportion, and the critical value you need for your 90% confidence interval. (Choose the correct critical value from the table of critical values provided.) When you are done, select "Compute". Sample size: Standard error: values Point estimate: 0.005 2-576 Margin of error Critical value: 50.010 2-326 50.025 1.960 90%% confidence interval 1-645 Compute FD 100 1.282 (b) Based on your sample, graph the 90% confidence interval for the population proportion of all college students who prefer printed textbooks to electronic textbooks. Enter the values for the lower and upper limits on the graph to show your confidence interval. For the point (*), enter the claim 0.45 from the study 90% confidence interval: 0.000 (c) Does the 90% confidence interval you constructed contradict the claim from the study? Choose the best answer from the choices below. No, the confidence interval does not contradict the claim. The proportion 0.45 from the study is inside the 90% confidence interval