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A recent Time magazine reported the following information about a sample of workers in Germany and the United States. United States Germany Average length of

A recent Time magazine reported the following information about a sample of workers in Germany and the United States.

United States Germany

Average length of workweek (hours) 42 38

Sample standard deviation of length of workweek (hours) 5 6

Sample size 600 700

We would like to determine whether or not there is a significant difference between the average workweek in the US and that in Germany.

Question 1: State the null and the alternative hypotheses. Use 1 to represent United States and 2 to represent Germany.

H0:

Ha:

1) Null: mu1 mu2; Alternative: mu1 < mu2

2)Null: p1 = p2; Alternative: p1 p2

3)Null: p1 p2; Alternative: p1 < p2

4)Null: p1 p2; Alternative: p1 > p2

5)Null: mu1 mu2; Alternative: mu1 > mu2

6)Null: mu1 = mu2; Alternative: mu1 mu2

Question 2: The value of the test statistic is

1) 178.32

2) 1.90

3) 13.11

Question 3: The test statistic is a

1) chi-square statistic

2) z-score

3) t-score

Question 4: What is the degrees of freedom for this test?

(Hint: You may not need to carry out the tedious calculation given in the Formula Table (posted on Canvas). A rough checking method discussed in the lecture video can be used here.)

1) 700

2) 10

3) 600

4) 1296

Question 5: What is the p-value?

1) less than 0.005

2) between 0.005 and 0.01

3) between 0.025 and 0.05

4) between 0.01 and 0.025

5) more than 0.05

Question 6: What is the critical value for this test? Assume 5% significance level.

1) 1.96

2) 1.645

3) 1.96

4) 1.645

Question 7: What is your conclusion? Would you conclude that there is a significant difference between the average workweek in the US and that in Germany?

1) Fail to reject the null. There is a significant difference between the average workweek in the US and that in Germany.

2) Fail to reject the null. There is no significant difference between the average workweek in the US and that in Germany.

3) Reject the null. There is a significant difference between the average workweek in the US and that in Germany.

4) Reject the null. There is no significant difference between the average workweek in the US and that in Germany.

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