A region bounded by f(x} = x, v = U, x = 1, and x = 4 is shown below. Find the volume of the solid formed by revolving the region about the xexis. -2 1234SE?B The base of a three-dimensional figure is bound by the line x = y + 3 and the y-axis on the interval [-2, 1]. Vertical cross-sections that are perpendicular to the y-axis are right triangles with height equal to 4. Find the volume of the figure. LY X 5432-1 1 2345 O O 17 4 0 5 O 15The base of a three-dimensional gure is bound by the line y = 2x + 3 on the interval [1, 3]. Vertical cross-sections that are perpendicular to the xaxis are right triangles with height equal to 4. Find the volume of the gure. cabanaacorn .110 123456?39 23 O? 32 O? 44 O? 028 The base of a three-dimensional figure is bound by the line y = va + 2 on the interval [-2, 2]. Vertical cross-sections that are perpendicular to the x-axis are squares. Find the volume of the figure. 7- X 3 2 -1 123 4 5 6 7 O O 23 3 0 8 O 32The base of a three-dimensional figure is bound by the circle x2 + y2 = 1. Vertical cross-sections that are perpendicular to the y-axis are right triangles with height equal to 4. Algebraically, find the area of each right triangle. X -2 2 -21 0 4V1-y2 0 V1-y2 O (1-y2)2 2 0 2/1-y2The base of a three-dimensional figure is bound by the graph y = sin(x) + 1. Vertical cross-sections that are perpendicular to the x- axis are rectangles with height equal to 3. Algebraically, find the area of each rectangle. NOW. X -5432-1 1 2345 o (sin(x) + 1) O 3 (sin(ac ) + 1) (sin(a) + 1) O 3 (sin(a) - 1)=in the area of the region bounded to the right by :1: = y2 + 2 and to the left by x = y\". The base of a three-dimensional gure is bound by the line y = 4 - x on the interval [-2, 2]. Vertical cross-sections that are perpendicular to the xaxis are right triangles with height equal to 4. Algebraically, nd the area of each triangle. Find the area of the region bounded to the right by a: = y2 + 2 and to the left by x = y? O 4.5 O 3.75 O Lola: Find the area of the region bounded above by y = x + 2 and below by y = a". X 4 -2 4 -2 4 O 13 3 O O 32 3 O 64 3Find the area of the region bounded above by y = 4 and below by y = 2:2 5