A report shows that 45% of residents in a certain country surveyed in 2016 got their news from local television. A similar survey conducted in 2017 found that 31% of residents in the same country got their news from local television. Assume the sample size for each poll was 1600. Complete parts (a) and (b) below. Question content area bottom Part 1 a. Construct the 95% confidence interval for the difference in the proportions of residents in the country who get their news from local television in 2016 and 2017. First check that the conditions for using a two-proportion confidence interval hold. You can assume that the sample is a random sample. The Random and Independent condition holds. The Large Samples condition holds. The Big Populations condition can reasonably be assumed to hold. The Independent Samples condition Part 2 The 95% confidence interval for the difference (2016 minus 2017) is ( 0.116, 0.244). (Round to three decimal places as needed.) Part 3 b. Based on your interval, do you think there has been a change in the proportion of residents in the country who get their news from local television? Explain. that the difference in sample standard