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A researcher is interested to determine the association of physical activity levels and BMI-for-age groups with blood pressure (BP) levels among 513 school-aged adolescents. Given
A researcher is interested to determine the association of physical activity levels and BMI-for-age groups with blood pressure (BP) levels among 513 school-aged adolescents. Given below is the SPSS output of the chi-square analysis between the variables.
BMI 3CAT * BP 2CAT Crosstab BP_2CAT normal BP high BP Total BMI_3CAT Underweight Count 35 0 35 % within BMI_3CAT 100.0% 0.0% 100.0% % within BP_2CAT 7.7% 0.0% 6.8% % of Total 6.8% 0.0% 6.8% normal weight Count 295 16 311 % within BMI 3CAT 94.9% 5.1% 100.0% % within BP_2CAT 65.3% 26.2% 60.6% % of Total 57.5% 3.1% 60.6% Overweight/Obese Count 122 45 167 % within BMI_3CAT 73.1% 26.9% 100.0% % within BP_2CAT 27.0% 73.8% 32.6% % of Total 23.8% 8.8% 32.6% Total Count 452 61 513 % within BMI 3CAT 88.1% 11.9% 100.0% % within BP_2CAT 100.0% 100.0% 100.0% % of Total 88.1% 11.9% 100.0%Chi-Square Tests Asymptotic Significance Value df (2-sided) Pearson Chi-Square 54.362 N 000 Likelihood Ratio 53.486 N 000 Linear-by-Linear 48.683 000 Association N of Valid Cases 513 a. 1 cells (16.7%) have expected count less than 5. The minimum expected count is 4.16.PA 2CAT * BP_2CAT Crosstab BP_2CAT normal BP high BP Total PA_2CAT Low and moderate PA Count 424 57 481 % within PA_2CAT 88.1% 11.9% 100.0% % within BP_2CAT 93.8% 93.4% 93.8% % of Total 82.7% 11.1% 93.8% High PA Count 28 4 32 % within PA_2CAT 87.5% 12.5% 100.0% % within BP_2CAT 6.2% 6.6% 6.2% % of Total 5.5% 0.8% 6.2% Total Count 452 61 513 % within PA_2CAT 88.1% 11.9% 100.0% % within BP_2CAT 100.0% 100.0% 100.0% % of Total 88.1% 11.9% 100.0%Chi-Square Tests Asymptotic Significance Exact Sig. (2- Exact Sig. (1- Value df (2-sided) sided) sided) Pearson Chi-Square .012 .912 Continuity Correction .000 1.000 Likelihood Ratio 012 .913 Fisher's Exact Test .784 .543 Linear-by-Linear 012 .913 Association N of Valid Cases 513 a. 1 cells (25.0%) have expected count less than 5. The minimum expected count is 3.81. b. Computed only for a 2x2 tableStep by Step Solution
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