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A researcher records the repair cost for88randomly selected refrigerators. A sample mean of$57.89and standard deviation of$23.69are subsequently computed. Determine the95%confidence interval for the mean repair

A researcher records the repair cost for88randomly selected refrigerators. A sample mean of$57.89and standard deviation of$23.69are subsequently computed. Determine the95%confidence interval for the mean repair cost for the refrigerators. Assume the population is approximately normal.

Step 1 of 2:Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.

Step 2 of 2:Construct the95%confidence interval. Round your answer to two decimal places.

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