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A sample of 100 is taken from a very large population known to be 5 % defective. Although the distribution is binomial , you would

A sample of 100 is taken from a very large population known to
be 5 % defective. Although the distribution is binomial,
you would like to use the normal distribution
What is the probability of finding 6 or fewer [ P( x <=6) ]
defectives in the sample?

I understand you do 6.5-.5/2.178 but once it gets to the z part I am lost

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