A second$-$order reaction has a rate constant of $0\mathrm{.}008500/($M $$ s$)$ at $30\backslash$deg C$.$ At $40\backslash$deg C$,$ the rate constant is $0\mathrm{.}03300/($M $$ s$).$

$($A$)$ What is the activation energy for this reaction?

Incorrect: Your answer is incorrect.

kJ$/$mol

$($B$)$ What is the frequency factor, A$?$

Incorrect: Your answer is incorrect.

$/($M $$ s$)$

$($C$)$ Predict the value of the rate constant at $55\backslash$deg C$.$

Incorrect: Your answer is incorrect.

$/($M $$ s$)$