A set of data items is normally distributed with a mean of 180 and a standard deviation of 24. Convert 132 to a zscore. (I> Z132=|:| (Type an integer or a decimal. Do not round until the nal answer. Then round to the nearest hundredth as needed.) A set of data items is normally distributed with a mean of 60 and a standard deviation of 9. Convert 54 to a z-score. <:> 254g (Do not round until the final answer. Then round to the nearest hundredth as needed.) Scores on a dental anxiety scale range from 0 (no anxiety) to 20 (extreme anxiety). The scores are normally distributed with a mean of 11 and a standard deviation of 4. Find the z-score for the given score on this dental anxiety scale. 13 213 = (Type an integer or a decimal.) Scores on a dental anxiety scale range from 0 (no anxiety) to 20 (extreme anxiety). The scores are normally distributed with a mean of 11 and a standard deviation of 4. Find the z-score for the given score on this dental anxiety scale. 20 220 = (Type an integer or a decimal.) The data in the accompanying bar graph are from a random sample of 881 adults. The graph shows four proposals to Proposals to Reduce Gun Violence reduce gun violence in a country and the percentage of surveyed adults who favored each of these proposals. Complete parts (a) and (b) below. 80- 62% 58% 60- 57% 55% Percentage of Adults Favoring the Proposal 40- 20- 0- Required Ban on Ban on Restrict amount or gun registration high-capacity assault type of ammunition magazines weapons purchases .. a. Find the margin of error for this survey. The margin of error is + %. (Do not round until the final answer. Then round to the nearest tenth as needed.)A set of data items is normally distributed with a mean of 300 and a standard deviation of 30. Find the data item in this distribution that corresponds to the given z-score. z=-6 <:> The data item that corresponds to z = - 6 is E. (Type an integer or a decimal.) Using a random sample of 2147 TV households, Acme Media Statistics found that 41% watched the final episode of "I Can't Take it Anymore!" a. Find the margin of error in this percent. b. Write a statement about the percentage of TV households in the population who tuned into the nal episode of "I Can't Take it Anymore!" a. The margin of error is t %. (Do not round until the final answer. Then round to the nearest hundredth as needed.)