A ship with a weight Wo has in seawater a depth of immersion of h and it displaces a volume of Vo. Before it enters the mouth of a river the weight of the ship is reduced by AW, which results in a decrease of the immersion to depth to h; and the displaced volume is now V1. When the ship enters the sweet water of the river the depth of immersion is hz and the corresponding displaced volume is V2 (See Fig 1) Calculate: - The volume Va (m") The size of the ships cross section A (m?) - The difference AV = V2 Vi (m") of the displaced Volume in sweet and salty water The depth of immersion hz in the sweet water (m). Psaly = 1.025 10 kg/m , Pwoet = 10 kg/m ,g = 10 m/s Fig 1 Wo = 2.0 109 AW 1.5 108 h 11 10.5