A shot putter threw an 8 lb 13 oz shot 67 ft, 2 in. Assuming the shot putter launched the shot at a 60" angle to the horizontal from 5.5 ft above the ground, what was the shot's initial speed? The acceleration due to gravity is 32 ft/sec". The shot's initial speed was vo = |ft/sec. (Do not round until the final answer. Then round to the nearest tenth as needed.)A shot putter threw an 8 lb 13 oz shot 67 ft, 6 in. Assuming the shot putter launched the shot at a 30" angle to the horizontal from 6 ft above the ground, what was the shot's initial speed? The acceleration due to gravity is 32 ft/sec-. The shot's initial speed was vo = 125.5 ft/sec. (Do not round until the final answer. Then round to the nearest tenth as needed.)A shot putter threw an 8 lb 13 oz shot 67 ft, 6 in. Assuming the shot putter launched the shot at a 30 angle to the horizontal from 6 it above the ground, what was the shot's initial speed? The acceleration due to gravity is 32 ft/sec-. The shot X (Do not X That's incorrect. Correct answer: 46.5 Your answer: 39.19 Similar question Next questionA shot putter threw an 8 lb 13 oz shot 67 ft, 2 in. Assuming the shot putter launched the shot at a 60" angle to the horizontal from 5.5 ft above the ground, what was the shot's initial speed? The acceleration due to gravity is 32 ft/sec". The shot X (Do not Try again. Since the shot is not being released from the origin, use the formula I= (Xo + (Vo cosa) t) it yo+ (vo sina) t- 5gt j to solve. OK