(a) Show that the concentration of R in a CSTR when the feed initially contains only A is: CA0CR=(1+k1k1K31+1)(1+Kbk3)+k31+k1k1(1+Kbk3) Where K3=(k1/k2)= equilibrium constant for the first reaction Kb=(k3/k4)= equilibrium constant for the second reaction (b) For both reactions irreversible, show what will happen to the results of part (a). (c) If the first reaction is very rapid, it is always close to its equilibrium as R is reacting further to S. Explain how this can be represented by k1 but Ka= finite, and find the expression for CR/CA0 by appropriately reducing the result of part (a). This is similar to rate-determining step situation, and is more simply derived by taking the first reaction to always be in instantaneous equilibrium, CACR/Ka