A side view of a 0.45 kg ball starts at the lowest position. It is then spun to rotate in a vertical circular path with angular acceleration 3.29 rad/s2 as shown in the figure. When the 1.2 m long string breaks, the ball is 1.0 m above the ground. [Answer in 2 significant figures] 1.2 m 8 f a = 3.29 h rad /$2 81= 0 1.0 m Xf