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A side view of a 0.45 kg ball starts at the lowest position. It is then spun to rotate in a vertical circular path

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A side view of a 0.45 kg ball starts at the lowest position. It is then spun to rotate in a vertical circular path with angular acceleration 3.29 rad/s as shown in the figure. When the 1.2 m long string breaks, the ball is 1.0 m above the ground. [Answer in 2 significant figures] a = 3.29 rad/s 1.2 m Of 9 = 0 vi h 1.0 m x

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