A simple random sample of 700 individuals provides 200 Yes responses. 3. What is the point estimate of the proportion of the population that would provide Yes responses (to 4 decimals)? b. What is your estimate of the standard error of the proportion (to 4 decimals)? c. Compute the 95% confidence interval for the population proportion (to 4 decimals). ( . ) A simple random sample of 700 elements generates a sample proportion 1') = 0.69. 3. Provide the 90% confidence interval for the population proportion (to 4 decimals). ( , ) b.Provide the 99% confidence interval for the population proportion (to 4 decimals). ( , ) In a surveyl the planning value for the population proportion is p* = 0.25. How large a sample should be taken to provide a 95% confidence interval with a margin of error of 0.07? Round your answer up to the next whole number. At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.040 for the estimation of a population proportion? Assume that past data are not available for developing a planning value for p *. Round up to the next whole number. One of the questions Rasmussen Reports included on a 2018 survey of 1,007 likely voters asked if the country is headed in the right direction. Representative data are shown in the le RightDirection. A response of Yes indicates that the respondent does think the country is headed in the right direction. A response of No indicates that the respondent does not think the country is headed in the right direction. Respondents may also give a response of Not Sure. Click on the datafile logo to reference the data. DATAr a. What is the point estimate of the proportion of the population of likely voters who do think that the country is headed in the right direction (to 4 decimals)? b. At 95% confidence, what is the margin of error (to 4 decimals)? c. What is the 95% confidence interval for the proportion of likely voters who do think that the country is headed in the right direction? (to 4 decimals)? to d. What is the 95% confidence interval for the proportion of likely voters who do not think that the country is headed in the right direction? (to 4 decimals)? to e. Which of the confidence intervals in parts (c) and (d) has the smaller margin of error? Why? The confidence interval in has the smaller margin of error. This is because in this part, i is farther away from - Select your answer - V . For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to less inflation in health care prices and employees paying for a larger portion of health care benefits. A recent Mercer survey showed that 55% of U.S. employers were likely to require higher employee contributions for health care coverage in the upcoming year. Suppose the survey was based on a sample of 748 companies. Compute the margin of error and a 90% confidence interval for the proportion of companies likely to require higher employee contributions for health care coverage in the upcoming yean The margin of error: (to 4 decimals) The 90% condence interval: ( , ) (to 4 decimals) For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to less inflation in health care prices and employees paying for a larger portion of health care benefits. A recent Mercer survey showed that 55% of U.S. employers were likely to require higher employee contributions for health care coverage in the upcoming year. Suppose the survey was based on a sample of 748 companies. Compute the margin of error and a 90% confidence interval for the proportion of companies likely to require higher employee contributions for health care coverage in the upcoming yean The margin of error: (to 4 decimals) The 90% condence interval: ( , ) (to 4 decimals) Fewer young people are driving. In 1995, 63.9% of people under 20 years old who were eligible had a driver's license. Bloomberg reported that percentage had dropped to 41.7% in 2016. Suppose these results are based on a random sample of 1,200 people under 20 years old who were eligible to have a driver's license in 1995 and again in 2016. a. At 95% confidence, what is the margin of error and the interval estimate of the number of eligible people under 20 years old who had a driver's license in 1995? Margin of error = (to four decimal places) Interval estimate = to (to four decimal places) b. At 95% confidence, what is the margin of error and the interval estimate of the number of eligible people under 20 years old who had a driver's license in 2016? Margin of error = (to four decimal places) Interval estimate 2 to (to four decimal places) c. Is the margin of error the same in parts (a) and (b)? - Select your answer - V Why, or why not? - Select your answer - V The Centers for Disease Control and Prevention (CDC) defines a healthy sleep duration to be at least seven hours per day. The CDC reports that the percentage of people who report a healthy sleep duration varies by marital status. The CDC also reports that in 2018, 67% of those who are married report a healthy sleep duration; 62% of those who have never been married report a healthy sleep duration; and 56% of those who are divorced, widowed, or separated report a healthy sleep duration. The file SleepHabits contains sample data on the sleeping habits of people who have never been married that are consistent with the CDC's findings. Use these data to answer the following questions. Click on the datafile logo to reference the data. DATAV 3. Develop a point estimate and a 95% confidence interval for the proportion of those who have never been married who report a healthy sleep duration. Point estimate (to 4 decimals) Confidence interval to (to 4 decimals) b. Develop a point estimate and a 95% confidence interval for the mean number of hours of sleep for those who have never been married. Point estimate (to 4 decimals) Confidence interval to (to 4 decimals) c. For those who have never been married, estimate the number of hours of sleep per day for those who report a healthy sleep duration (to 4 decimals). Hint(s) Check My Work The National Center for Education Statistics reported that 47% of college students work to pay for tuition and living expenses. Assume that a sample of 450 college students was used in the study. 3. Provide a 95% confidence interval for the population proportion of college students who work to pay for tuition and living expenses. (to 2 decimals) ( . ) b. Provide a 99% confidence interval for the population proportion of college students who work to pay for tuition and living expenses. (to 2 decimals) ( . ) c. What happens to the margin of error as the confidence is increased from 95% to 99%? The margin of error becomes - Select your answer - v Hint(s) Check My Work A USA Today/CNN/Gallup survey of 379 working parents found 196 who said they spend too little time with their children because of work commitments. a. What is the point estimate of the proportion of the population of working parents who feel they spend too little time with their children because of work commitments? (to 4 decimals) b. At 95% confidence, what is the margin of error? (to 4 decimals) c. What is the 95% confidence interval estimate of the population proportion of working parents who feel they spend too little time with their children because of work commitments (to 4 decimals)? ( . ) Hint(s) Check My Work The Pew Research Center has conducted extensive research on social media usage. One finding, reported in June 2018, was that 78% of adults aged 18 to 24 use Snapchat. Another finding was that 45% of those aged 18 to 24 use Twitter. Assume the sample size associated with both ndings is 500. Round your answers to four decimal places. a. Develop a 95% confidence interval for the proportion of adults aged 18 to 24 that use Snapchat. to b. Develop a 99% confidence interval for the proportion of adults aged 18 to 24 who use Twitter. to c. In which case, part (a) or part (b), is the margin of error larger? - Select your answer - v In 2014, the Centers for Disease Control and Prevention reported the percentage of people 18 years of age and older who smoke. Suppose that a study designed to collect new data on smokers and nonsmokers uses a preliminary estimate of the proportion who smoke of 0.30. a. How large a sample should be taken to estimate the proportion of smokers in the population with a margin of error of 0.02? Use 95% confidence. Remove all commas from your answer before submitting. Round your answer to next whole number. b. Assume that the study uses your sample size recommendation in part (a) and finds 520 smokers. What is the point estimate of the proportion of smokers in the population? (to 4 decimals) c. What is the 95% confidence interval for the proportion of smokers in the population? (to 4 decimals) ( . )