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a) sin-1/ If y = sin -1(x), then sin(y) = x, _ - TT -sys_ Therefore, to find y = sin -1/ _ V 1(

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a) sin-1/ If y = sin -1(x), then sin(y) = x, _ - TT -sys_ Therefore, to find y = sin -1/ _ V 1( - 42 ) we must find an angle y whose sine is - V2 There are many possible angles with this sine, but the range of y = sin-1(x) is restricted to the interval , and so y must be in this interval. X

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