A single$-$phase full bridge inverter circuit, has load $R=2$ and de source $V_s=230V.$ Find the value of power delivered to the load in watts only due to the fundamental component of the load current.

a$)21439$ W

b$)2142\mathrm{.}5$ W

The square wave operation of single phase VSI inverter contains spectrum of harmonies. The amplitudes are

a$)$ Directly proportional to their harmonic order

b$)$ Not related to their harmonic order

c$)$ Inversely proportional to their harmonic order

d$)$ None of these

The fundamental harmonic of Single$-$phase full bridge inverter has $36$ phase shift, while the total harmonic distortion of the current is $18\%.$ The true power factor is

a$)PF=0\mathrm{.}865$lag

b$)PF=0\mathrm{.}796$lag

c$)PF=0\mathrm{.}925$lag

d$).$

Two quadrant operation of full$-$wave controlled rectifier means

a$)$ Fixed firing angle at given load inductance

b$)$ The firing angle varies in the range of minimum angle to values less than $90.$

c$)$ The rectifier regenerates reactive energy to the network

In square wave operation mode of $3$ phase VSI $($with $$ control$),$ the VSI

a$)$ Can control the load voltage

b$)$ Cannot control the load voltage except by means of dc link voltage

c$)$ Cannot control the load voltage

d$)$ Cannot control the load voltage except by means of de link current

Single phase VSI inverter with $ma=0\mathrm{.}75$&$mf=41.$ The source voltage is $220$ V dc and the frequency of output is $50$ Hz energizing heater with $R=5.$ find the value of fundamental voltage and current and frequency of the ${43}^{rd}$ harmonic.

a$)Vml=165V,$Iml$=33A$&$ftr=2150Hz$

b$)Vml=280V,$Iml$=65A$&$ftr=4200Hz$

c$)Vml=311V,$Iml$=62\mathrm{.}2A$&$ftr=2050Hz.$

d$)$

Boost dc chopper with output dc power of $2000$ W consumed by $10$ resistance, with chopping frequency of $10$ kHz and voltage ripples of $2\mathrm{.}6\%$ across $240F$ capacitance. The dc input and output voltage are

a$)Vs=220V$&$Vo=120\mathrm{.}45V$

b$)V_s=56\mathrm{.}55V$&$Vo=122\mathrm{.}45V$

c$)V_s=53\mathrm{.}2V$&$V_O=141\mathrm{.}42V$

d$)$

The effect of freewheeling diode connected across the rectifier is to :

a$-$ Eliminate the negative output voltage and releasing the stored energy

b$-$ Eliminate the over commutation voltage

c$-$ Eliminate the overlapping effect and realize a return current path

The overlapping angle may increase by

a$-$ decreasing the firing angle at given frequency

b$-$ the overlapping angle does not affect by increasing the firing angle

c$-$ decreasing the firing angle and increasing the supply voltage