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A slab with thickness of 0.05m is at initial temperature of 25C. The slab is heated by passing a hot gas over its surfaces. The

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A slab with thickness of 0.05m is at initial temperature of 25C. The slab is heated by passing a hot gas over its surfaces. The gas temperature T=600C and h=200W/m2.K. Slab is made from a materials with K=0.5W/m.K and =3.5107m2/s. a) Determine the time required to achieve 75% of maximum possible energy transfer. b) Determine lowest temperature in the slab after 30 minutes. Table 7.4-2 Approximate solutions for diffusion and conduction (valid for Fo>0.2 ) Fo=L2t=r02t,=TiTTT,0=C1exp(12Fo) Conduction in a slab L is defined as the distance from the center of the slab to the surface. If one surface is insulated, L is defined as the total thickness of the slab. =0cos(1x);QoQ=11sin(1)0 PLANE WALL \begin{tabular}{lll} Bi & 1(rad) & C1 \\ \hline & & \\ 0.01 & 0.0998 & 1.0017 \\ 0.02 & 0.1410 & 1.0033 \\ 0.03 & 0.1732 & 1.0049 \\ 0.04 & 0.1987 & 1.0066 \\ 0.05 & 0.2217 & 1.0082 \\ 0.06 & 0.2425 & 1.0098 \\ 0.07 & 0.2615 & 1.0114 \\ 0.08 & 0.2791 & 1.0130 \\ 0.09 & 0.2956 & 1.0145 \\ 0.10 & 0.3111 & 1.0160 \\ 0.15 & 0.3779 & 1.0237 \\ 0.20 & 0.4328 & 1.0311 \\ 0.25 & 0.4801 & 1.0382 \\ 0.30 & 0.5218 & 1.0450 \\ 0.4 & 0.5932 & 1.0580 \\ 0.5 & 0.6533 & 1.0701 \\ 0.6 & 0.7051 & 1.0814 \\ 0.7 & 0.7506 & 1.0919 \\ 0.8 & 0.7910 & 1.1016 \\ 0.9 & 0.8274 & 1.1107 \\ 1.0 & 0.8603 & 1.1191 \\ 2.0 & 1.0769 & 1.1795 \\ 3.0 & 1.1925 & 1.2102 \\ 4.0 & 1.2646 & 1.2287 \\ 5.0 & 1.3138 & 1.2402 \\ 6.0 & 1.3496 & 1.2479 \\ 7.0 & 1.3766 & 1.2532 \\ 8.0 & 1.3978 & 1.2570 \\ 9.0 & 1.4149 & 1.2598 \\ 10.0 & 1.4289 & 1.2620 \end{tabular}

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