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. A small block of mass M is released from rest at the top of the curved frictionless ramp shown above. The block 9 slides

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. A small block of mass M is released from rest at the top of the curved frictionless ramp shown above. The block 9 slides down the ramp and is moving with a speed 3.5m. ' when it collides with a larger block of mass 1.5M at rest at h the bottom of the incline. The larger block moves to the [ right at a speed 2 vi: immediately after the collision. _ Express your answers to the following questions in terms of the given quantities and fundamental constants. (a) Determine the height h of the ramp from which the small block was released. (b) Determine the speed of the small block after the collision. (c) The larger block slides a distance D before coming to rest. Determine the value of the coefficient of kinetic friction it between the larger block and the surface on which it slides. (d) Indicate whether the collision between the two blocks is elastic or inelastic. Justify your answer. Questions 35 refer to the graph shown to the right: Block 1 of mass V6106\"? (\"1'51 m1 and block 2 of mass m2 are sliding along the same line on a horizontal frictionless surface when they collide at time to. The graph shows the velocities of the blocks as a function of time. 4. Blocks 1 and 2 Which htock has the greater moss, and what information indicates this? Circle the Correct Answer _ _________ (A). Block 1, because it had a greater speed before the collision. {8} Block 1, because the velocity alter the collision is in the same direction as its velocity before the collision. (Cl Block 2, because it had a smaller speed before the collision. {0} Block 2, because the final velocity is closer to the initial velocity of block 2 than it is to the initial velocity of block 1. What would the graph look like if the two blocks had the same mass? Use either conservation of momentum or the impulse-momentum principle to explain your answer... How does the kinetic energv ofthe m'ohtock system otter the coitisiori compare with its kinetic energy before the coltision, and why? Circle the Correct Answer (A) it is less, because the blocks have the same velocity after the collision, so some of their kinetic energy was transformed into internal energy. (B) it is less, because the blocks have velocities in opposite directions before the collision, so some of their kinetic energy cancels. (C) it is the same, because the collision was instantaneous, so the effect of external forces during the collision is negligible. (D) it is the same, because the blocks have the same velocity after the collision, and there is no friction acting on them. Explain what type of collision this is, and use that to explain why the kinetic energy is less or the same after the collision

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