A small electric immersion heater is used to heat $66$ g of water for a cup of instant coffee. The heater is labeled $“130$ watts$”($it converts electrical energy to thermal energy at this rate$).$ Calculate the time required to bring all this water from $20\backslash$deg C to $100\backslash$deg C$,$ ignoring any heat losses. $($The specific heat of water is $4186$ J$/$kg$·$K$.)$