A small high-speed commercial centrifuge has the following net cash flows and abandonment values over its useful life. The firm's MARR is 8\% per year. Determine the optimal time for the centrifuge to be abandoned if its current MV is $8,000 and it won't be used for more than five years. Click the icon to vew the interest and annuity table for discrete compounding when MARR =8% per year: The centrifuge should be retained for year(s) before abandonment. (Round to the nearest whole number. Type o if the centrifuge should be abandoned immediately.) \begin{tabular}{|c|c|c|c|c|c|c|} \hline \multicolumn{7}{|c|}{ Discrete Compounding; i=8%} \\ \hline \multicolumn{4}{|c|}{ Single Payment } & \multicolumn{2}{|c|}{ Uniform Series } & \multirow{3}{*}{\begin{tabular}{c} Capital \\ Recovery \\ Factor \end{tabular}} \\ \hline & Compound & & Compound & & Sinking & \\ \hline & \begin{tabular}{l} Amount \\ Factor \end{tabular} & \begin{tabular}{c} Present \\ Worth Factor \end{tabular} & \begin{tabular}{l} Amount \\ Factor \end{tabular} & \begin{tabular}{c} Present \\ Worth Factor \end{tabular} & \begin{tabular}{l} Fund \\ Factor \end{tabular} & \\ \hline & To Find F & To Find P & To Find F & To Find P & To Find A & To Find A \\ \hlineN & \begin{tabular}{c} Given P \\ F/P \end{tabular} & \begin{tabular}{l} Given F \\ P/F \end{tabular} & Given A & \begin{tabular}{c} Given A \\ P/A \end{tabular} & Given F & Given P \\ \hline 1 & 1.0800 & 0.9259 & 1.0000 & 0.9259 & 1.0000 & 1.0800 \\ \hline 2 & 1.1664 & 0.8573 & 2.0800 & 1.7833 & 0.4808 & 0.5608 \\ \hline 3 & 1.2597 & 0.7938 & 3.2464 & 2.5771 & 0.3080 & 0.3880 \\ \hline 4 & 1.3605 & 0.7350 & 4.5061 & 3.3121 & 0.2219 & 0.3019 \\ \hline 5 & 1.4693 & 0.6806 & 5.8666 & 3.9927 & 0.1705 & 0.2505 \\ \hline 6 & 1.5869 & 0.6302 & 7.3359 & 4.6229 & 0.1363 & 0.2163 \\ \hline 7 & 1.7138 & 0.5835 & 8.9228 & 5.2064 & 0.1121 & 0.1921 \\ \hline 8 & 1.8509 & 0.5403 & 10.6366 & 5.7466 & 0.0940 & 0.1740 \\ \hline \end{tabular} Print Done