A soap film, nsmp = 1.33, with a thickness of t = 821nm, fills a glass cell, ugh\" = 1.55. The top of the cell is open and has air above it. Consider a ray of white light that strikes the film. Pad of that light rayr is transmitted through the film, reflects at the soaplglass boundary, and then travels back through the film and into the air toward the eye (the distance from the airlsoap boundary to the eye is d). The rest of it is reflected at the airlsoap boundary and travels a distance, d, from the boundary to the eye. At the eye, it undergoes interference. (c) How far (in symbols) does this light ray travel? (d) In symbols, what is the path length difference (or difference in the distances the two light rays travel)? (e) . v PartA Consider the light ray that is only reflected at the airisoap film surfaceit does not enter the film. Is there a phase change of 180 O for this reflection? O Yes ONo m muest Answer 7 PartB How far (in symbols) does this light ray travel? O d+Amp/2 O d+2t+Asoap/2 Q d O d+Asoap Part C Consider the light ray that enters the soap film and then is reflected at the soap film/glass boundary. Is there a phase change for this reflection? O no O yes Submit Request Answer Part D How far does this light ray travel to get to the eye? O d+ 2t + soap/2 O d+ t+ soap/2 O d+t+ 21soap O d+ 2t + soap Submit Request Answer Part E In symbols, what is the path length difference (or difference in the distances the two light rays travel)? O 2t + 31soap/ 2 O 2t + soap/2 O 2t + 2xsoap O 2t Submit Request AnswerV Part F Using the condition for destructive interference, find the wavelength of the m = 3 minimum, in nanometers (nm). AEQ Asoap = nm Submit Request