A special-purpose 30-horsepower electric motor has an efficiency of 91%. Its purchase and installation price is $2,300 A second 30-horsepower high-efficiency motor can be purchased for $3,300, and its efficiency is 93%. Either motor will be operated 3,500 hours per year at full load, and electricity costs $0.10 per kilowatt-hour (kWh). MARR = 12% per year, and neither motor will have a market value at the end of the eight-year study period. a. Which motor should be chosen? b. For an incremental investment of $1,000 in the more efficient motor, what is the PW of the energy savings over the eight-year period? Recall that 1 hp = 0.746 kW Click the icon to view the interest and annuity table for discrete compounding when /= 12% per year. a. The PW of the motor with the efficiency of 91% is $-45,060. (Round to the nearest dollar.) The PW of the motor with the efficiency of 93% is $-45,143. (Round to the nearest dollar.) Which motor should be chosen? Choose the correct answer below. The 91% efficiency motor The 93% efficiency motor b. The PW of the net benefit from the incremental investment into a more efficient motor is $ (Round to the nearest dollar)