A stainless steel hemisphere and its copper floor from a two-surface enclosure. Calculate the radiation heat transfer (Q12) from the 0.2 m diameter stainless steel hemisphere (1 = 0.4) to the copper floor/plate (E2 =0.15) that forms its base. The hemisphere is kept at 300 C and the base at 100C 1 300 C E1=0.4 D=0.2 m C 0.15 2 Term Lecturer Name Surname Engineering Midterm 2 Midterm a exam 2021 2022 Spring Duration Assoc. Prof. Dr. Aya Hasanoglu 2002 + 134 pt) A composite spherical shell of inner radius -0.25 m is constructed from lead of outer radius pro 30 merand AISI 302 stainless steelhof outer cediulus -0.326The cavity is filled with radioactive wasters that fenerate heat at a rate of 32.7 kW. It is proposed to submerge the container in oceanic waters that are te of the container. Does the inner surface of the container resist the generated heat, when it is submerged in the outer ocean? (The melting point of the lead is 601 K) Thermal conductivities: kienu 35.3 W/mC kuto=15.1 W/mC 2. (34 nt1