A stone is thrown with an initial velocity of 35 Ws from the edge of a bridge that is 4-4- ft above the ground. The height of this stone above the ground t seconds alter it is thrown is t} = 'lEit2 + 36H 44. If a second stone is thrown from the ground, then its height above the ground altert seconds is given by g[t} = '1E~t2 + vt, where \"'0 is the initial velocity.r of the second stone. Determine the value 0va such that the two stones reach the same high point. ..... ) When an object that is thrown upwards reaches its highest point [iust before it starts to fall back to the ground}, its 1' will be zero. Therefore, to nd the maximum height of the object thrown from the bridge, use the I: equation, E