A straight line is expressed by the equation, where is the slope of the line and is the -intercept, i.e. the coordinate of the location where the line crosses the -axis (see Figure 1) Define a class named Line whose attributes and to model a line. Use inline style to define the class. Use the provided template file, main.epp to write your code. The requirements for the program are as follows:

1 Define a constructor that accepts four parameters which are , and , representing the coordinates and of two points that the line passes through. The slope and -intercept of the line are then calculated by:

Declare this constructor such that it can also serve as a default constructor. In this case, it will model a line that passes through the points and , which should result in and .

Sol195:

Here is the implementation of the Line class with the constructor that meets the requirements mentioned:

class Line {

private:

double m, c; // slope and y-intercept

public:

// Constructor that accepts two points (default is (0,0) and (1,1))

Line(double x1=0, double y1=0, double x2=1, double y2=1) {

m = (y2 - y1) / (x2 - x1); // calculate slope

c = y1 - m*x1; // calculate y-intercept

}

// Getters for slope and y-intercept

double getSlope() const {

return m;

}

double getYIntercept() const {

return c;

}

};

This class has a constructor that accepts four parameters, but with default values set to (0,0) and (1,1), it can serve as a default constructor as well. The slope and y-intercept are calculated in the constructor using the provided formula. The class also has getters for the slope and y-intercept.