A study has shown that the probability distribution ofX, the number of customers in line (including the one being served, if any) at a checkout counter in a department store, is given byP(X= 0) = 0.20,P(X= 1) = 0.25,P(X= 2) = 0.20,P(X= 3) = 0.20, andP(X 4) = 0.15. Consider a newly arriving customer to the checkout line. Round your answers to two decimal places, if necessary.

What is the probability that this customer will not have to wait behind anyone?

What is the probability that this customer will have to wait behind at least one customer?

On average, the newly arriving customer will have to wait behind how many other customers? Answer with the best approximation possible with the data you are given.