A study indicates that 850 20 year old spend a mean of 130 minutes watching video on their smartphones per month assume that the amount of time watching video on a smartphone per months normal distributed and that the standard deviations 20 minutes. Complete parts (a) through (d) below What is the probability that an 18-20 24 year old spend less than 100 minutes watching video on his or her smartphone per month? [Round to four decimal places as needed) OA PX100NORM DIST130,130.20.10.000 O PX100 NORM DISTI99.130.20.1-0.0067 OC PX1001 NORM DIST130,160.20.1-0.9332 OD PX100 HORMOIST100,130.20.1 0.0000 6. What is the postatity that in t8 to 24-year-old sponda datanse 100 and 540 minutes watching video on bli or her unashona par mantie? Pound to tow deciena to decina as needed OA PHONORM DIST140.150.20.1-NORM DIST(100.150.20.1-0.6247 OB. P(10.140)=NORM.DIST(140,130,20,1)=0.6915 B. P(X>140)=1-NORM DIST(140,130,20,0)=0.9824 C. PX>140)=1-NORM. DIST(140,130,20,1)=0.3085 D. P(X>140)=1-NORM.DIST(141,130,20,1)=0 2912 d. Five percent of all 18- to 24-year-olds will spend less than how many minutes watching video on his or her smartphone per month? (Round to two decimal places as needed) A. P(x)=0.05 --> NORM.DIST(0,05,130,20)=0.00 OB. P(X)*0.05 > 1,00 -0,06 -0.85 NORM INV(0,85,130,20)162,90 OC. P(X)*0.05 > NORM.INV(0.05,130,20)-97.10 on PIX#5 -> 100-NORM INVIN 05 130 2012