A study was conducted and it was reported that 34 34 out of 253 253 students said they had an all-nighter in the last semester. Use the statistical tool to answer the following. Hint (a) What is the standard error for the proportion of college students who had all-nighters? Standard Error = (b) Assume the level of confidence is 95 % 95%. What is the z critical value, z , that corresponds to the confidence level? = z = (c) Calculate the margin of error for the sample proportion of college students who had all-nighters from the equation for the margin of error ( ) (ME): = ME=z (standard error). Notice how the values in the web tool match the calculated value from the equation. = ME=