a. Suppose the program counter, PC, has the value 0x12345678. What is the value of PC after executing the following jump instruction?

j 0x10

Note: The meaning of "0x10" here is that the j instruction has the value 0x10 (= 16 in decimal) in its 26-bit immediate field.

Answer: The value of PC after execution (in hex) = 0x_________ (give all 8 hexits, leading "0x" already given)

b. Suppose the program counter, PC, has the value 0x12345678. What is the value of PC after executing the following instruction?

beq $0, $0, -5

Note: The meaning of "-5" here is that the branch instruction has the value -5 in its 16-bit immediate field.

Answer: The value of PC after execution (in hex) = 0x_________ (give all 8 hexits, leading "0x" already given)

c. Suppose the program counter, PC, has the value 0x12345678. What is the value of PC after executing the following instruction?

bne $0, $0, 5

Note: The meaning of "5" here is that the branch instruction has the value 5 in its 16-bit immediate field.

Answer: The value of PC after execution (in hex) = 0x_________ (give all 8 hexits, leading "0x" already given)

The correct answers are 10000040, 12345668, and 1234567c. Please show me how you got the answers.