A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35. 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station's 11 p.m. news is found for each sample. The results are given in the table below. Age Group Watch 55 or 11 p.m. News? 18 or less 19 to 35 36 to 54 Older Total Yes 49 59 61 84 253 No 201 191 189 166 747 Total 250 250 250 250 1.000 (a) Let p1, p2, p3. and p4 be the proportions of all viewers in each age group who watch the station's 11 p.m. news. If these proportions are equal, then whether a viewer watches the station's 11 p.m. news is independent of the viewer's age group. Therefore, we can test the null hypothesis He that p1, p2, p3, and p4 are equal by carrying out a chi-square test for independence. Perform this test by setting a = .05. (Round your answer to 3 decimal places.) x"2 = m H0: independence A marketing research firm wishes to study the relationship between wine consumption and whether a person likes to watch professional tennis on television. One hundred randomly selected people are asked whether they drink wine and whether they watch tennis. The following results are obtained: Watch Do Not Tennis Watch Tennis Tota'Ls Drink Wine 5 50 55 Do Not Drink Wine 15 30 45 Totals 20 80 100 (a) For each row and column total, calculate the corresponding row or column percentage. Row 1 Row 2 Column 1 Column 2 (b) For each cell, calculate the corresponding cell, row, and column percentages. (Round your answers to the nearest whole number.) Watch Tennis Do Not Watch Tennis Drink Wine Do Not Drink Wine