a. ) The 896 residents of a retirement community were tested for the flu and 120 tested positive.What is the 95% confidence interval around the true proportion infected?

Fill in the blanks:

n = _____,sample proportion infected (p-hat) = ________; sampling proportion not infected (q-hat) = ______

= _____ and /2 = ______so, the Critical +z-value (z_c) = _________;

CalculatedE(Margin of Error boundary)=z_c*SQRT [( p * q)/n]= ________(don't forget this formula !)

Confidence Interval:p-hat - E < population proportion (p)

State what this means:

b.) PROPORTION problem (use z)

35000 students took Stat 200 and 29000 passed.At the 1% significance level, what is the confidence interval around this proportion?

1.)x = _______;n = ____________;p-hat =___________;q-hat = ___________;z_c = ____________

2.)Using the formula for E, what is this margin of error?______________ (show setup and final value)

3.)What is the Confidence Interval?_________ < p < ______________

c.) Twenty-six residents in a development were surveyed as to how many days the "bread-winner(s)" had been laid off due to Covid-19.The sample mean (x-bar) was 31 and the sample Standard Deviation was 4.Construct an = 5% Confidence Interval around the population mean based on this sample data.

1.) Is this a z or t problem and why?_____________________________________

2.) What is the critical z or t value?________

3.)What is the formula for "E"?______________________, Plug in the values and show this setup and the final number

4.)What is the = 5% CI:__________ < < _____________