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A thin, flexible chain hangs in the form of a catenary; y = coshx = (1/2) (ex + e-X). Find the moment of inertia


A thin, flexible chain hangs in the form of a catenary; y = coshx = (1/2) (ex + e-X). Find the moment of inertia of the catenary from x = -1 to x = 1, with respect to the x- and y-axes. /y=coshx X

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