A tube is coated on the inside with naphthalene and has an inside diameter of $20mm$ and a length of $1\mathrm{.}10m.$ Air at $318K$ and an average pressure of $101\mathrm{.}3$kPa flows through this pipe at a velocity of $0\mathrm{.}80\frac{m}{s}.$ Assuming that the absolute pressure remains essentially constant, calculate the concentration of naphthalene in the exit air. Use the physical properties given below

$D_{AB}=6\mathrm{.}92{10}^{-6}\frac{m^2}{s}$ and the vapor pressure, $p_{Ai}=74\mathrm{.}0Pa$

For air, visocity $=1\mathrm{.}932{10}^{-5}$Pas, and density $=1\mathrm{.}114k\frac{g}{m^3}.$

$(5)$

$0$

$0$

$0$

$0$

$\frac{?}{\text{b}\text{a}\text{r}}(D_{AB}L{)}^{U1}{?}^{Iv}R{e}^{Iv}S\frac{c}{b}ar(L)\frac{,}{b}ar(4)$