A uniform thin rod of mass m = 4.2 kg and length L = 1.4 m can rotate about an axle through its center. Four forces are acting on it as shown in the figure. Their magnitudes are F1 = 2.5 N, F2 = 4.5 N, F3 = 11 N and F4 = 15 N. F2 acts a distance d = 0.11 m from the center of mass.

Part (a) Calculate the magnitude 1 of the torque due to force F1, in newton meters. 1 = 1.750 Correct!

Part (b) Calculate the magnitude 2 of the torque due to force F2 in newton meters. 2 = 0.3500 Correct!

Part (c) Calculate the magnitude 3 of the torque due to force F3 in newton meters. 3 = 0.000 Correct!

Part (d) Calculate the magnitude 4 of the torque due to force F4 in newton meters. 4 = 0.000 Correct!

PLEASE HELP SOLVEPart (e) Calculate the angular acceleration of the thin rod about its center of mass in radians per square second. Let the counter-clockwise direction be positive.