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A volume of 85.0 mL of H20 is initially at room temperature (22.00 C). A chilled steel rod at 2.00 C is placed in

A volume of 85.0 mL of H2O is initially at room temperature (22.00 °C). A chilled steel rod at 2.00 °C is placed in the water 

A volume of 85.0 mL of H20 is initially at room temperature (22.00 C). A chilled steel rod at 2.00 C is placed in the water. If the final temperature of the system is 21.10 C, what is the mass of the steel bar? Use the following values: specific heat of water = 4.18 J/(g. specific heat of steel = 0.452 J/(g.C) Express your answer to three significant figures and include the appropriate units. View Available Hint(s) mass of the steel = 50.12 Submit Previous Answers X Incorrect; Try Again; One attempt remaining

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