A wall 4 cm thick has a conductivity of 40 W/(m g and is generating heat at a rate of 1 MW/m. The wall surface on either side is cooled by a fluid Save Answer at 20C with a convection cooeficient of 200 W/(m "C). If the wall is analyzed using a steady-state, finite-difference analysis with3 node points shown, the equation for the temperature at the center node would be: Plate T. 2 cm -2 em OT1- (TO + T2V2 + 10C a. b. T1= (TO + T2/2 T1 - (TO - T2V0.04 Od T1- (TO+ T2+ 10CV2 T1- (TO+ T2)/2 + 40C e. O T1 (TO+ T2+ 40CV2