A water supplying company wished to estimate the average amount the private customers pay per month. A random sample of 25 customers' bills produced a sample mean of $30 and a sample standard deviation of $5. (Hint: In the previous question, $5 is the standard deviation of the whole population, while now $5 is a standard deviation of just a sample of 25 customers.) c) Find a 95% confidence interval for the population mean in this situation (that is, the situation of the previous question). O 37.94