A way to make artificial diamond is to squeeze carbon atoms under intense pressure: about 725,000...
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A way to make artificial diamond is to squeeze carbon atoms under intense pressure: about 725,000 Psi (~ 5,000 MPa) at elevated temperature. The intense temperature and pressure bond the carbon atoms to each other in a unique arrangement: one carbon atom to four other carbon atoms. Mechanical engineering student John co-ops in a research laboratory seeking to invent a process to make synthetic diamond at lower pressure. During an experiment, a part designed by John is simultaneously subjected to 2 loads: Load 1 generates these stresses (in MPa) in the part: x = 18, ay = 21, O = 2, Txy = 30, Tyz = 0, Tzx = 0, Load 2 generates these stresses (in MPa) in the part: dx = 0, 0y = 0, 0 = 23, Txy = 0, Tyz = 25, Tzx = 36. (a) Determine the stresses (x, y, z, Txy, Tyz, Tzx) caused by the two loads. How many non- zero shear stress are there among (ay, ay, Oz, Txy Tyz Tzx)? " (b) Determine the principal normal stresses 0, 02, and 03. (Sort them by magnitude. Use o to denote the largest principal normal stress, and 3 to denote the smallest, i.e., 0 > 0 > 03.) (c) Determine the yield strength oo of the material that will give a safety factor against yielding of X = 3 when the Maximum Shear Stress Yield Criterion (Tresca Yield Criterion.) is used. A way to make artificial diamond is to squeeze carbon atoms under intense pressure: about 725,000 Psi (~ 5,000 MPa) at elevated temperature. The intense temperature and pressure bond the carbon atoms to each other in a unique arrangement: one carbon atom to four other carbon atoms. Mechanical engineering student John co-ops in a research laboratory seeking to invent a process to make synthetic diamond at lower pressure. During an experiment, a part designed by John is simultaneously subjected to 2 loads: Load 1 generates these stresses (in MPa) in the part: x = 18, ay = 21, O = 2, Txy = 30, Tyz = 0, Tzx = 0, Load 2 generates these stresses (in MPa) in the part: dx = 0, 0y = 0, 0 = 23, Txy = 0, Tyz = 25, Tzx = 36. (a) Determine the stresses (x, y, z, Txy, Tyz, Tzx) caused by the two loads. How many non- zero shear stress are there among (ay, ay, Oz, Txy Tyz Tzx)? " (b) Determine the principal normal stresses 0, 02, and 03. (Sort them by magnitude. Use o to denote the largest principal normal stress, and 3 to denote the smallest, i.e., 0 > 0 > 03.) (c) Determine the yield strength oo of the material that will give a safety factor against yielding of X = 3 when the Maximum Shear Stress Yield Criterion (Tresca Yield Criterion.) is used.
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Related Book For
Biochemistry Concepts and Connections
ISBN: 978-0321839923
1st edition
Authors: Dean R. Appling, Spencer J. Anthony Cahill, Christopher K. Mathews
Posted Date:
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