A well has the following profile: Casing Total depth 16,400' (vertical well) Drill string: 16" Open Hole, Surface casing 13 3/8" OD and 12 3/7" ID of 68.00 lb/ft set at 2000'. 12.5" Open Hole, Intermediate Casing 9 5/8" OD and ID of 8 2/3", 47 lb/ft, set at 8,458' 8.5" Open Hole, Drilling liner 7" (6" ID) (Grade N-80) interval between 8,400' to 14,200' Open Hole, Bit diameter 5.5" 5" drill pipe 19.50 lb/ft nominal weight, (4.276" ID) surface to 8300'. 3 1/2 drill pipe 13.30 lb/ft nominal weight between 8,300' to 15,200'. (For the ID on the 3 1/2" drill pipe remember that density of steel is 65.5 lb/gal) Drill collars, 4 3/4" OD, x 2 1/4" ID, 46.70 ppf, 15200' to TD. Surface mud system: 3 mud tanks, each 9' high, 7' wide, 36' long. With the entire drill string out of the hole: Mud level in tanks No. 1 & 2 is 72" of mud and tank No. 3 has 60" of mud (M.W: 11 ppg) For the following questions 2 to 9, do calculation by hand using equations from the lectures. 2 Calculate the total capacity of the surface mud system in bbl. 3 Calculate total mud volume in the three tanks in bbls. bbls bbls 4 Calculate the capacity in bbl/ft for each well section. bbl/ft 5 Calculate total hole volume with the entire drill string out of the hole. bbls 6 Calculate the displacement of the 5" drill pipe. bbl/ft 7 Calculate the displacement of the complete drill string. bbls 8 Calculate the total hole volume with the bit on the bottom. 9 Calculate the hydrostatic pressure at bottom of hole. bbls psi