a-1.Complete the ANOVA table. Fill in the table that is included in this image.(Round your SS, MS, andFvalues to 2 decimal places andp-value,Fcrit to 4 DECIMAL PLACES.)

a-2.Use = 0.05 level of significance, compute the critical value.(Round your answer to 2 decimal places.)

The value of the critical value F is:

b.Using thet-test from Chapter 11, computet.(Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.)

c.There is any difference in the mean test scores. (choose the correct phrase to complete the statement)

(Reject, Fail to reject) H0. There is ( a statistically significant difference, no statistically significant difference) in the mean scores between lecture and internet- based formats.

When only two treatments are involved, ANOVA and the Student's t-test (Chapter 11) result in the same conclusions. Also, for computed test statistics, 1'2 = F. To demonstrate this relationship, use the following example. Fourteen randomly selected students enrolled in a history course were divided into two groups, one consisting of six students who took the course in the normal lecture format. The other group of eight students took the course as a distance course format. At the end of the course, each group was examined with a 50-item test. The following is a list of the number correct for each of the two groups. Traditional Lecture Distance 37 50 35 46 41 49 40 44 35 41 34 42 45 43 Click here for the Excel Data File a-1. Complete the ANOVA table. (Round your SS, MS. and Fvalues to 2 decimal places and p-value, Fcrit to 4 decimal places.)