AB is a vertical tower of p units high. D and C are in the same horizontal plane as B, the foot of the tower. The angle of elevation of A from D is x. BDC=y and DCB = 0. The distance between D and C is k units. D X X P B C 6.1.1 Express p in terms of DB and x. 6.1.2 Hence prove that: p= ksin@tanx sinycose+cosysine (2) (5) 6.2 Find BC to the nearest meter if x = 51,7, y=62,5, p = 80 m and k = 95 m. (4 [11