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About 75% of young adult Internet users (ages 18 to 29) watch online video. Suppose that a sample survey contacts a simple random sample of

About 75% of young adult Internet users (ages 18 to 29) watch online video. Suppose that a sample survey contacts a simple random sample of 1000 young adult Internet users and calculates the proportion in this sample who watch online video.

What is the mean of the sampling distribution?

=

Find the standard deviation of the sampling distribution (round to the nearest thousandth)

=

What is the probability that between 71% and 77% (inclusive) them watch videos online?

P(0.71 0.77) =

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