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According to a recent study, 15% of peanut MOM's are brown, 12% are yellow, 28% are red, 18% are blue, 18% are orange, and 8%

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According to a recent study, 15% of peanut MOM's are brown, 12% are yellow, 28% are red, 18% are blue, 18% are orange, and 8% are green. Assume these proportions are correct and suppose you randomly select four peanut MOM's from an extra-large bag of the candies. Calculate the following probables. Also calculate the mean and standard deviation of the distribution. Round all solutions to four decimal places, if necessary. Compute the probability that exactly three of the four M&M's are red. P(x = 3) 0.0630 x Compute the probability that two or three of the four MOM's are red. P(x = 2 or z = 3) 0.3079 x Compute the probability that at most three of the four MOM's are red. P(x 3) 0.0691 x

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