According to a recent study, 21% of peanut M&M's are brown, 6% are yellow, 5% are red, 29% are blue, 24% are orange, and 15% are green. Assume these proportions are correct and suppose you randomly select six peanut M&M's from an extra-large bag of the candies. Calculate the following probablities. Also calculate the mean and standard deviation of the distribution. Round all solutions to four decimal places, if necessary. Compute the probability that exactly four of the six M&M's are orange. P(x=4)=P(x=4)= Compute the probability that four or five of the six M&M's are orange. P(P(x=4x=4 or x=5x=5)=)= Compute the probability that at most four of the six M&M's are orange. P(x4)=P(x4)= Compute the probability that at least four of the six M&M's are orange. P(x4)=P(x4)= If you repeatedly select random samples of six peanut M&M's, on average how many do you expect to be orange? == orange M&M's With what standard deviation? == orange M&M's