According to a report analyzing dog breeds, the mean height of mature Black Russian Temers is 69.8 cm, with a standard deviation of 2.78. A researcher believes that, because of changes to breeding practicesr the true standard deviation, 0, is not 2.78. To test this, she selects a random sample of 27 mature Black Russian Terriers and finds that their mean height is 70 cm, with a standard deviation of 3.86. Do these data provide enough evidence, at the 0.01 level of significance, to reject the claim that the standard deviation of mature Black Russian Terriers' heights is equal to 2.78? Assume that the heights of mature Black Russian Terriers are approximately normallyr distributed. Per'orm a twotailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. (If necessaryr consult a list of formulas.) (a) State the null hypothesis H and the alternative hypothesis H . 0 1 ii 0 is HD : o = 2.78 _ A x 5 p H1 : o 4': 2.78 (b) Determine the type of test statistic to use. leisquare Y Degrees of freedom: = '5 3 (c) Finc the value of the test statistic. (Round to three or more decimal places.) i