According to a research lrlstilutinn, the average hotel prlce ln a certain yearwas $91 95 Assume the population standard deviation is $2500 and that a random sample oi 50 hotels was seleded Complete parts a through d below, 3. Calculate the standard error of The mean 0i = S 3.54 (Round to two decimal places as needed) b. What is the probability that the sample mean will be less Than $933? P (Em $93) : 0,5124 (Round to four decimal places as needed) c. What is the probability that the sample mean wlll be more than $98? P(S $93) = anus (Round to four decimal places as needed) d. What is the probability that the sample mean will be between $91 and $92? P($91525$92) 2 (Round to four decimal places as needed)