According to the question Average time of every curtomer reach = 15 min Average time for customer to eat = 12 min only one seat 2 people can wait . A The rate of Arrives = 1= 60. : 4 person hy 15 1 the rate of Arrival = 1 = 4 person/ hr B The service rate = M = 10 = 5 person hr 12 so the serviu rate = 15 person hy = N Average number of customer in restausent including watting Area. LB = 1 -3 8 = M So L= 415 = 415 1- 415 =4 215 So Average number of wtomer in rettawent indueling waiting. Area = 4. Portability that total 2 customer in restaurant including waiting area . in= s. Po 1= numberof- kerson Po = 1-s So 2 = ( 8 ) 4 ( 1 - 8 ) = (4 )2(1-45 ) 8 = 16 125 so probability = 16 125